The area of a ΔABC is one unit. DE is a straight line parallel to BC, joining the points D and E on AB and AC respectively such that AD : DB = 1 : 6. The ratio of the areas of ΔADE and ΔABC is:
Show answer & explanation
Correct answer: D
Explanation
Correct answer is option 4 i.e. 1 : 49
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Concept |
Understanding |
Application |
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Similarity of triangles
Area of triangle A/Area of triangle B = (side of A)2/(side of B)2
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DE is a straight line parallel to BC AD : DB = 1 : 6
AD = x, DB = 6x AB = x + 6x = 7x |
Area of ΔADE/Area of ΔABC = (AD)2/(AB)2 = 12/72 = 1/49 |