SSC CGL 2024 PYQ — Question 71

SSC CGL - 12 Sep 2024 - Shift 2 • Quantitative Aptitude • Q71

Solve the following:

[(2.5+1.5)2÷4 of12×8−1]\bigg [ {(2.5+1.5)^2 \div 4\ of {1\over2}\times8-1} \bigg]

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 63.

According to the given question, applying the rule of BODMAS,

[(2.5+1.5)2÷4 of12×8−1]\bigg [ {(2.5+1.5)^2 \div 4\ of {1\over2}\times8-1} \bigg]

⇒ [16÷4 of12×8−1]\bigg [ {16 \div 4\ of {1\over2}\times8-1} \bigg]

⇒ [16÷2×8−1]\bigg [ {16 \div 2\times8-1} \bigg]

⇒ 8 × 8 - 1

⇒ 64 - 1 = 63

Hence the required answer is 63.