Solve the following. (2Sin22ᵒ) / (Cos68ᵒ) - (2Cot75ᵒ) / (5tan15ᵒ) - (8tan45ᵒtan20ᵒtan40ᵒtan50ᵒtan70ᵒ) / (5)

Solve the following. (2Sin22ᵒ) / (Cos68ᵒ) - (2Cot75ᵒ) /…

Solve the following.

(2Sin22^o) / (Cos68^o) - (2Cot75^o) / (5tan15^o) - (8tan45^otan20^otan40^otan50^otan70^o) / (5)

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e 0

⇒ (2Sin22^o) / (Cos68^o) - (2Cot75^o) / (5Tan15^o) - (8Tan45^oTan20^oTan40^oTan50^oTan70^o) / (5)

(Sin(90^o - θ) = Cosθ, Tan(90^o - θ) = Cotθ)

⇒ (2Cos68^o) / (Cos68^o) - (2Tan15^o) / (5Tan15^o) - (8Tan45^oCot70^oCot50^oTan50^oTan70^o) / (5)

⇒ 2 - 2/5 - 8/5

⇒ 0