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SSC CGL 2023 PYQ — Question 68

SSC CGL - 17 July 2023 - Shift 4 • Quantitative Aptitude • Q68

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sin4θ+cos4θ1−2sin2θ.cos2θ=\frac{sin^4 \theta + cos^4 \theta}{1-2sin^2 \theta. cos^2 \theta}= ___________.

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 1.

Given that

⇒ sin4θ+cos4θ1−2sin2θ.cos2θ\frac{sin^4 \theta + cos^4 \theta}{1-2sin^2 \theta. cos^2 \theta}

⇒  [sin2θ+cos2θ]2−2sin2θ.cos2θ1−2sin2θ.cos2θ\frac{[sin^2 \theta + cos^2 \theta]^2 - 2sin^2 \theta. cos^2 \theta}{1-2sin^2 \theta. cos^2 \theta}

⇒ 1−2sin2θ.cos2θ1−2sin2θ.cos2θ\frac{1 - 2sin^2 \theta. cos^2 \theta}{1-2sin^2 \theta. cos^2 \theta}

⇒ 1