SSC CGL 2023 PYQ — Question 69

The correct answer is option 3 i.e. $\frac{1}{679}$

Given that

$\frac{432\times432+247\times247-432\times247}{432\times432\times432+247\times247\times247}$

Formula used

a³ + b³ = (a + b)(a² + b² - ab)

⇒ $\frac{432\times432+247\times247-432\times247}{(432+247)(432\times432+247\times247-432\times247)}$

⇒ $\frac{1}{(432+247)}$

⇒ $\frac{1}{679}$