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SSC CGL 2023 PYQ — Question 69

SSC CGL - 18 July 2023 - Shift 4 • Quantitative Aptitude • Q69

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Simplify the following expression.

710\frac{7}{10} ÷ 37\frac{3}{7} of (2310+235)(2\frac{3}{10}+ 2\frac{3}{5}) + 15\frac{1}{5} ÷ 1251\frac{2}{5} - 27\frac{2}{7}

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Correct answer: C

Explanation

The correct answer is Option 3 i.e. 421\frac{4}{21}.

710\frac{7}{10} ÷ 37\frac{3}{7} of (2310+235)(2\frac{3}{10}+ 2\frac{3}{5}) + 15\frac{1}{5} ÷ 1251\frac{2}{5} - 27\frac{2}{7}

By using the BODMAS rule,

⇒ 710\frac{7}{10} ÷ 37\frac{3}{7} of (2310+135)({23\over{10}} + {13\over{5}}) + 15\frac{1}{5} ÷ 757\over5 - 27\frac{2}{7}

⇒ 710\frac{7}{10} ÷ 37\frac{3}{7} of (2310+2610)({23\over{10}} + {26\over{10 }}) + 15\frac{1}{5} ÷ 757\over5 - 27\frac{2}{7}

⇒ 710\frac{7}{10} ÷ 37\frac{3}{7} of 4910{49\over{10}}  + 15\frac{1}{5} ÷ 757\over5 - 27\frac{2}{7}

⇒ 710\frac{7}{10} ÷ 2110\frac{21}{10} + 15\frac{1}{5} ÷ 757\over5 - 27\frac{2}{7}

⇒ 710\frac{7}{10} × 1021\frac{10}{21} + 15\frac{1}{5} × 575\over7 - 27\frac{2}{7}

⇒ 13\frac{1}{3} + 17\frac{1}{7} - 27\frac{2}{7}

⇒ 1021\frac{10}{21} - 27\frac{2}{7} = 421\frac{4}{21}