SSC CGL 2024 PYQ — Question 68

The correct answer is Option 1 i.e. 0.

$[(5{1\over 2}-3{1\over 3})$ of $1{5\over 13}+1-2×3{5\over 2}÷2{3\over 4}$]

⇒ $[({11\over 2}-{10\over 3})$ of ${18\over 13}+1-2×{11\over 2}÷{11\over 4}$]

⇒ $[({33-20\over 6})$ of ${18\over 13}+1-2×{11\over 2}\times{4\over 11}$]

⇒ $[{13\over 6}$ × ${18\over 13}+1-2×{11\over 2}\times{4\over 11}$]

⇒ 3 + 1 - 2 × 2

⇒ 4 - 4 = 0