SSC CGL 2025 PYQ — Question 71

SSC CGL - 16 Sep 2025 - Shift 1 • Quantitative Aptitude • Q71

Simplify: (212+3.6)÷0.75+(1.25×45)(2{1 \over 2} + 3.6) \div 0.75 + (1.25 \times {4 \over 5})

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 13715{137 \over 15}.

(212+3.6)÷0.75+(1.25×45)(2{1 \over 2} + 3.6) \div 0.75 + (1.25 \times {4 \over 5})

⇒ (52+3.6)÷0.75+(1)({5 \over 2} + 3.6) \div 0.75 + (1)

⇒ (2.5+3.6)÷0.75+(1)(2.5+ 3.6) \div 0.75 + (1)

⇒ 6.10.75+1{6.1 \over 0.75} + 1 = 61075+1{610 \over 75} + 1

⇒ 12215+1{122 \over 15} + 1 = 13715{137 \over 15}