Simplify : [(23)+(45÷27)]÷[(32)−(56×34)][({2 \over 3}) + ({4 \over 5} \div {2 \over 7})] \div [({3 \over 2}) - ({5 \over 6} \times {3 \over 4})] [(32)+(54÷72)]÷[(23)−(65×43)] A416105 {416 \over 105}105416 B 418110 {418 \over 110}110418 C 425250 {425 \over 250}250425 D 526350 {526 \over 350}350526 Show answer & explanationCorrect answer: AExplanationThe correct answer is option 1 i.e. 416105 {416 \over 105}105416. [(23)+(45÷27)]÷[(32)−(56×34)][({2 \over 3}) + ({4 \over 5} \div {2 \over 7})] \div [({3 \over 2}) - ({5 \over 6} \times {3 \over 4})] [(32)+(54÷72)]÷[(23)−(65×43)] ⇒ [(23)+(45×72)]÷[(32)−(58)][({2 \over 3}) + ({4 \over 5} \times {7 \over 2})] \div [({3 \over 2}) - ({5 \over 8} )] [(32)+(54×27)]÷[(23)−(85)] ⇒ [(23)+(145)]÷[(12−58)][({2 \over 3}) + ({14 \over 5} )] \div [({12-5 \over 8}) ] [(32)+(514)]÷[(812−5)] ⇒ [(5215)]÷[(78)][({52 \over 15}) ] \div [({7 \over 8}) ] [(1552)]÷[(87)] ⇒ [(5215)]×[(87)][({52 \over 15}) ] \times [({8\over 7}) ] [(1552)]×[(78)] = 416105 {416 \over 105}105416