Reema runs times as fast as Rekha. Given this, Reema allows Rekha a lead of 50 meters to Rekha in a friendly race competition. What is the distance from the starting point where both Reema and Rekha meet?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 250 m.
Speed = Distance/Time
Let the speed of Rekha be 4x
Speed of rReema= (5/4) × 4x = 5x
Distance covered by Reema be y
Distance covered by rRekha= (y - 40)
According to the question;
⇒ 5x/4x = y/(y - 50)
⇒ 5y - 250 = 4y
⇒ y = 250
The distance from the starting point where both Reema and Rekha meet = 250 m