SSC MTS 2022 PYQ — Question 71

SSC MTS - 20 July 2022 - Shift 1 • Quantitative Aptitude • Q71

Points P and Q are 400 km apart. A person starts from P towards Q at 6 a.m. at a speed of 20 km/h. Another person starts from Q towards Pat 6 : 30 a.m. at a speed of 30 km/h. At what time will they meet?

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 2 : 18 p.m.

Distance = Speed × time

Relative speed in opposite direction = S1 + S2

Distance between P and Q = 400km

Speed of first-person = 20km/h

Speed of the second person = 30 km/h

So, distance covered by the first person in 30 min = 20 × 30/60 = 10 km

Now both person running towards each other at 6 : 30 am

distance between them = 400 - 10 = 390

Time = 390/(20 + 30) = 39/5 hours 

= 7 hours 48 min

So, they meet = 6 : 30 am +  7 hours 48 min = 2 : 18 pm