Point P lies outside a circle with centre O. Tangents PA and PB are drawn to meet the circle at A and B respectively. If √APB = 80º, then √OAB is equal to:
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 40º
OA is perpendicular to PA.
OP is the angle bisector of APB.
AOP = BOP = 180 - 90 - 40 = 50°
OAB = OBA ( OA = OB)
OAB = (180 - 100)/2 = 40°.