Pipe V1 can be fill an empty tank in 8 hours. Pipe V2 can fill the same tank in 16 hours. Pipe V3 can empty the same, completely filled, tank in 12 hours. If three pipes are opened simultaneously, then in how much time will the tank get completely filled?
Show answer & explanation
Correct answer: D
Explanation
Correct Answer is option 4 i.e. 48/5 hours
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Understanding |
Application |
Calculation |
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Pipe V1 and V2 can fill an empty tank in 8 and 16 hours respectively. Pipe V3 can empty the same tank in 12 hours. |
Suppose Capacity of tank = 48 units |
⇒ LCM of 8, 16 and 12 = 48 |
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Efficiency = Work/Time |
So, Efficiency of pipe V1 = 6 |
⇒ 48/8 = 6 |
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Efficiency = Work/Time |
So, Efficiency of pipe V2 = 3 |
⇒ 48/16 = 3 |
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Efficiency = Work/Time |
So, Efficiency of pipe V3 = -4 |
⇒ 48/12 = 4 |
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When all pipes are opened simultaneously. |
Cumulative efficiency = 6 + 3 – 4 = 5 |
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Time = Work/Efficiency |
Hence, Time taken = 48/5 hours |
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