SSC CHSL 2020 PYQ — Question 69

SSC CHSL - 18th October 2020 - Shift 1 • Quantitative Aptitude • Q69

PA and PB are tangents to the circle and O is the centre of the circle. The radius is 5 cm and PO is 13 cm. If the area of the triangle PAB is M, then the value √(M/15) is:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e. 24/13.

Understanding/Application

In triangle OAP -

OA2 + AP2 = OP2

52 + AP2 = 132

AP2 = 169 - 25

AP = 12 cm

Similarly, BP = 12 cm

In triangle OAP -

sin x = OA/OP

sin x = 5/13

cos x = AP/OP

cos x = 12/13

In triangle ACP -

sin x = AC/AP

5/13 = AC/12

AC = 60/13

Similarly, BC = 60/13

cos x = CP/AP

12/13 = CP/12

CP = 144/13

Area of triangle PAB = M

1/2. AB. CP = M

1/2. (AC + BC). CP = M

1/2. (60/13 + 60/13). 144/13 = M

1/2 × 120/13 × 144/13 = M

M = (60 × 144)/169

M/15 = (60 × 144)/(169 × 15)

√(M/15) = 24/13