SSC CHSL 2024 PYQ — Question 52

SSC CHSL - 10 July 2024 - Shift 2 • Quantitative Aptitude • Q52

P got married 15 years ago. Today her age is 135\frac 3 5 times her age at the time of her marriage. At present her son's age is 15\frac 1 5of her age. What was her son's age 4 years ago as a fraction of P's age at that time?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 19\frac{1}{9}.

Let P's age at the time of her marriage be x

She got married 15 years ago,

Present age = x + 15

Today her age is 135\frac 3 5 times her age at the time of her marriage

⇒ x + 15 =  135\frac 3 5 x

⇒ x + 15 = 85\frac 8 5x

⇒ 5(x + 15) = 8x

⇒ 5x + 75 = 8x

⇒ 3x = 75

⇒ x = 25

So, P's present age = x + 15 = 25 + 15 = 40 years

At present her son's age is 15\frac 1 5 of her age

Son's present age = 15\frac 1 5 × 40 = 8 years

So, Son's age 4 years ago = 8 - 4 = 4 years

P's age 4 years ago = 40 - 4 = 36 years

So,

Fraction = Son's age 4 years ago/P's get 4 years ago

⇒ 436\frac {4} {36} = 19\frac 1 9