O is the center of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 26 cm.
O is the center of this circle. Tangent drawn from a point P, touches the circle at Q.
PQ = 24 cm and OQ = 10 cm
If a tangent is drawn on a circle from an external point, it is perpendicular to the radius at the point of tangency.
In a right-angled triangle,
Hypotenuse² = Base² + Height²
According to the concept,
∠OOP 90°
Hence, OP is the hypotenuse of △OQP which is a right-angled triangle.
Now, OP = √(242 + 102) = 26 cm
The value of OP is 26 cm.