Let x be the least number which when divided by 15, 18, 20 and 27, the remainder in each case is 10 and x is a multiple of 31. What least number should be added to x to make it a perfect square ?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 ie 39.
x = k LCM(16, 18, 20, 27) + 10
x = 540k + 10
k = 1, x = 550
k = 2, x = 1090
k = 3, x = 1630
k = 4, x = 2170
Minimum number need to be added to 2170
= 39 (to make it a perfect square)