Let O be the centre of a circle. PA and PB are tangents to the circle from a point P outside the circle and A and B are points on the circle. If angle APB = 50º, then angle OAB is equal to:
Show answer & explanation
Correct answer: A
Explanation
The correct answer in option 1 i.e. 25º

In quadrilateral OAPB, ∠O + ∠A + ∠P + ∠B = 360°
⇒ ∠O + 90° + 50° + 90° = 360°
⇒ ∠O = 360° - 230° = 130°
In ΔOAB, OA = OB = radius
⇒ ∠O + ∠B + ∠A = 180° ( By the property of angle sum )
⇒ 130° + ∠B + ∠A = 180° ( ∠OAB = ∠OBA )
⇒ ∠A + ∠B = 180° - 130° = 50°
(∵ Angles opposite to equal sides are equal.)
⇒ ∠A + ∠A = 50°
⇒ ∠A = 50°/2 = 25°