SarkariPYQ

SSC Selection Post 2022 PYQ — Question 66

SSC Selection Post - Higher Secondary Level - 08 Feb 2022 - Shift 2 • Quantitative Aptitude • Q66

Back to paper

Let Δ ABC ~ ΔPQR and ar(△ABC)ar(△QPR){ar(\bigtriangleup ABC){} \over ar(\bigtriangleup QPR)}= 25169{25{} \over 169}. If AB = 15 cm, BC = 7 cm, and AC = 8 cm, then PQ (in cm) is equal to:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 39.

(Area ABC)/(Area PQR) = (AB/PQ)2 = 25/169

⇒ AB/PQ = √(25/169) = 5/13

⇒ 15/PQ = 5/13

⇒ PQ = (15 × 13)/5 = 39 cm