SSC CGL 2021 PYQ — Question 74

SSC CGL - 13 Aug 2021 - Shift 1 • Quantitative Aptitude • Q74

Let △ABC ~ △PQR and  = 14449\frac{144}{49}. If AB = 12 cm, BC = 7 cm and AC = 9 cm, then PR (in cm) is equal to:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 214\frac{21}{4}

Given :

  △ABC ~ △PQR and  = 14449\frac{144}{49}

AB = 12 cm, BC = 7 cm and AC = 9 cm

Concept used :

Similarity of triangles

  = (AB/PQ)2 = (BC/QR)2 = (AC/PR)2      ----- (1)

Calculations :

⇒ Using equation (1), we get

⇒ 14449=(ACPR)2\frac{144}{49} = (\frac{AC}{PR})^2

⇒ 14449=9PR\sqrt{\frac{144}{49}} = \frac{9}{PR}

⇒ (12/7) = 9/PR

⇒ PR = (7 × 3)/4

⇒ PR = 21/4