In the given figure, AD is the bisector of angle ∠CAB and BD is the bisector of angle ∠CBF. If the angle at C is 34o, the angle ∠ADB is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e 17o
| Understanding | Application |
| We will use the exterior angle theorem in the given question to find the required angle. |
Let the angle ∠CAD & ∠DBF be 'x' & 'y' respectively. In the triangle ABC, by the exterior angle theorem ⇒ ∠CBF = ∠CAB + ∠ACB ⇒ 2y = 2x + 34o ⇒ y - x = 17o In the triangle ABD, by the exterior angle theorem ⇒ ∠DBF = ∠DAB + ∠ADB ⇒ y = x + ∠ADB ⇒ ∠ADB = y - x = 17o |