In the given figure, ABCD is a square of side 14 cm. E and F are mid points of sides AB and DC, respectively. EPF is a semicircle whose diameter is EF. LMNO is a square. What is the area (in cm²) of the shaded region ?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 94.5
Area of square ABCD = 14 × 14 = 196 cm2
Area of semicircle = (π × 72)/2 = 77 cm2
Diaognal LN = 14/2 = 7 cm
So, Side of square LMNO = 7/√2 cm
So, Area of square LMNO = (7/√2)2 = 49/2 = 24.5
Hence,
Area of shaded region = 196 - (77 + 24.5) = 94.5