In ΔOPQ, ∠O = 50°, ∠P = 70°, and the bisectors of ∠P and ∠Q meet at R. Find ∠PRQ.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e. 115°.
Sum of angles in a triangle = 180°
Then,
∠Q = 180° − (50° + 70°) = 60°
The bisector of ∠P divides it into two angles of 70°/2 = 35
The bisector of ∠Q divides it into two angles of 60°/2 = 30°
Point R is the intersection of the angle bisectors of ∠P and ∠Q.
At point R (intersection of angle bisectors of ∠P and ∠Q):
∠PRQ = 180° − (35° + 30°) = 180° − 65° = 115°