SSC CGL 2022 PYQ — Question 12

SSC CGL Tier II - Quant - 29 Jan 2022 • Quantitative Aptitude • Q12

In △LMN, LM = 5√2 cm, LN = 13 cm and √LMN = 135º. What is the length (in cm) of MN?

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Correct answer: C

Explanation

The correct answer is option 3 i.e. 7

Let the length of MN be 'a'.

By using the cosine rule with respect to 135°

Cos135° = a2+(52)2−(13)22×52×a\frac{a^2 + (5\sqrt2)^2 - (13)^2}{2 \times 5\sqrt2 \times a}

−12\frac{-1}{\sqrt2} = a2+50−1692×52×a\frac{a^2 + 50 - 169}{2 \times 5\sqrt2 \times a}

⇒ a2  + 10a - 119 = 0

⇒ a2  + 17a - 7a - 119 = 0

⇒(a + 17)(a - 7)= 0

⇒ a = 7