A and B can do a work in 26days. B and C together can complete the same work in 48 days, while A and C together can complete the same work in 30 days. How long (in days) will A alone take to complete 60% of the work?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 24
A + B = 80/3 days.
B + C = 48 days.
A + C = 30 days.
Let the total work = 240 units.
Efficiency of A + B = 9 units/day....(1)
Efficiency of B + C = 5 units/day......(2)
Efficiency of A + C = 8 units/day.....(3)
on adding eq (1, 2, 3) we get,
2(A + B + C) = 22 units.
A + B + C one day efficiency = 11 units.
Efficiency of A = 11 - 5 = 6 units/day.
60% of work = 60/100 × 240 = 144 units.
Time taken by A to complete 144 units of work = 144/6 = 24 days.