SSC CHSL 2024 PYQ — Question 55

The correct answer is option 3 i.e. 8.38.

As seen in the figure

∆FEG ~ ∆XEY ( AA similarity criterion )

Given that

Ar(XYFG) = 44 m²

Let the area of ∆EXY = x

The ratio of the areas of 2 similar triangles is equal to the ratio of the squares of their corresponding sides 

Ratio of EX : EF = 2 :5

Hence, $\frac{x}{x + 44}$  = ($\frac{2}{5}$)²

Solving for x we get

21x = 176

⇒ x = 8.38 

Hence, the area of ∆EXY is 8.38 m²