SSC CGL 2020 PYQ — Question 71

SSC CGL - 4th March 2020 Shift 2 • Quantitative Aptitude • Q71

In △ABC, D and E are the points on sides AC and BC, respectively such that DE || AB. F is a point on CE such that DF || AE. If CE = 6 cm, and CF = 2.5 cm, then BC is equal to:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e 14.4 cm

Given;

DE || AB & DF || AE & CE = 6 cm and CF = 2.5 cm

As we can see that in △CDF and in △CAE, 

CD/CA = CF/CE (Similar triangle property)

So,

CD/CA = 2.5/6 .................. (1)

Now, In △CDE and △CAB, 

CD/CA = CE/CB (Similar triangle property)

From equation 1:

2.5/6 = 6/BC  .................. (2)

⇒ BC = (6 × 6) / 2.5

⇒ BC = 14.4 cm