If, 7sin2θ – cos2θ + 2sinθ = 2, 0° < θ < 90°, then the value of 
is :
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e 
Given, 7sin2θ - cos2θ + 2sinθ = 2
So, 7sin2θ - (1 - sin2θ) + 2sinθ - 2 = 0
⇒ 8sin2θ + 2 sinθ - 3 = 0
On solving the equation we get, sinθ = 1/2 , which means θ = 30º.
Now, Putting the value of θ =30º in the required equation, we get
⇒ (sec60º + cot60º) / (cosec60º+ tan60º)
⇒ (2 + 1/√3) / (2/√3 + √3)
⇒ (2√3 + 1) / 5