In △ ABC, a median AD is drawn to side BC. What is the ratio of the area of △ ABD to the area of △ ACD?

In △ ABC, a median AD is drawn to side BC. What is the…

In $\triangle$ ABC, a median AD is drawn to side BC. What is the ratio of the area of $\triangle$ ABD to the area of $\triangle$ ACD?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 1:1.

Median AD divides BC into two equal parts

$\triangle$ ABD and $\triangle$ ACD have: the same height (from A), equal base (BD = DC)

So, areas are equal

Ratio = 1 : 1