In a trapezium ABCD, AB, and DC are parallel to each other with a perpendicular distance of 8 m between them. Also, (AD) = (BC)= 10 m, and (AB) = 15 m < (DC). What is the perimeter (in m) of the trapezium ABCD?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 62
Given that
In a trapezium ABCD
(AD) = (BC)= 10 m, and (AB) = 15 m < (DC)
and a perpendicular distance of 8 m between AB and CD
In right angled triangle APD, DP = √(100 - 64) = √36 = 6 m
DP = QC = 6 m
Hence, the perimeter of the trapezium = AB + BC + CD +DA = 15 + 10 + (6 + 15 + 6) + 10
= 62 m