In a circle with centre O, PAX and PBY are the tangents of the circle at points A and B, from an external point P. Q is any point on the cirlce such that ∠QAX = 59° and ∠QBY = 72°. What is the measure of ∠AQB?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e 49°.

From the given figure one can conclude that,
OA = OB = OQ = Radius.
Now OAQ = 90° - 59° = 31°.
OBY = 90° - 72° = 18°.
Here OA = OQ so OAQ = OQA = 31°.
OB = OQ so OBQ = OQB = 18°
AQB = OQA + OQB = 31 + 18 = 49°.