In a circle with centre O. AB is a chord of length 10 cm . Tangents at a point A and B intersect outside the circle at P. If OP = 2 OA, then find the length (in cm) of AP.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 10
Here, OA = OB = x cm
OP = 2x cm
AB = 10 cm
AQ = BQ = AB/2 = 10/2 = 5 cm
OAP ~ OAQ
⇒ OP/OA = AP/AQ
⇒ 2x/x = AP/5
⇒ AP = 10 cm