In a circle, chord AB and chord CD intersect at E such that AE : EB = 2 : 3 and CE : ED = 5 : 2. If AB = x and CD = y, which of the following is true?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. .

AE : EB = 2 : 3
Let AE = 2k, EB = 3k
AB = 5k = x
CE : ED = 5 : 2
Let CE = 5m, ED = 2m
CD = 7m = y
By the intersecting chords theorem: AE × EB = CE × ED
(2k) × (3k) = (5m) × (2m)
⇒ 6k2 = 10m2
⇒ 3k2 = 5m2
⇒ k2 = (5/3)m2
x2 = (5k)2 = 25k2 = 25 × (5/3)m2 = (125/3)m2
y2 = (7m)2 = 49m2
x2/y2 = [(125/3)m2]/(49m2) = 125/147