A chord in a circle with radius 10 cm subtends an angle of 90° at the center. What is the area of the minor segment?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. (25 - 50) sq. cm.
Area of minor segment = Area of sector – Area of triangle
Sector angle = 90°
Area of sector = (90/360) × πr2 = (1/4) × π × 102 = 25π sq. cm
Triangle area = (1/2) × r2 × sin 90° = (1/2) × 102 × 1 = 50 sq. cm
Segment area = (25π – 50) sq. cm