SSC CHSL 2021 PYQ — Question 59

SSC CHSL - 5 Aug 2021 - Shift 1 • Quantitative Aptitude • Q59

In a circle, AB and DC are two chords. When AB and DC are produced, they meet at P. If PC = 5.6 cm, PB = 6.3 cm and AB = 7.7 cm, then the length of CD is∶

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. 10.15 cm.

Given, PC = 5.6, PB = 6.3, AB = 7.7

PA = PB + AB = 6.3 + 7.7 = 14

As we know,

PC × PD = PB × PA

⇒ 5.6 × PD = 6.3 × 14

⇒ PD = (6.3 × 14)/5.6

⇒ PD = 15.75

⇒ PD = PC + CD

⇒ 15.75 = 5.6 + CD

∴ CD = 15.75 – 5.6 = 10.15 cm