SSC CHSL 2022 PYQ — Question 66

SSC CHSL - 2 June 2022 - Shift 2 • Quantitative Aptitude • Q66

If (x3 + y3)2/3 = (x2 + y2), then the value of (x2 + y2)/xy, x ≠ 0, y ≠ 0, is

Show answer & explanation

Correct answer: A

Explanation

The correct answer is Option 1 i.e. 2/3

Given:

(x3 + y3)2/3 = (x2 + y2)

According to the given question, (x3 + y3)2/3 = (x2 + y2)

Now, taking cubes on both sides, we get

⇒ (x3 + y3)2 = (x2 + y2)3

⇒ x6 + 2x3y3 + y6 = x6 + 3x4y2 + 3x2y4 + y6

⇒ 2x3y3 = 3x2y2(x2 + y2)

⇒ 2xy = 3(x2 + y2)

⇒ (x2+y2)xy=23{(x^2 + y^2) \over xy} = {2 \over 3}

Hence, the required answer is 2/3.