If (x3 – 2√2 y3) ÷ (x – √2y) = (Ax2+ Bxy + Cy2) then, (2A + 4√2 B – 4C) = ?
Show answer & explanation
Correct answer: D
Explanation
Correct Answer is option 4 i.e. 2
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Concept |
Understanding |
Application |
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x3 + y3 = (x + y) (x2 + y2 – xy)
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Given (x3 – 2√2 y3) ÷ (x - √2y) = Ax2 + Bxy + Cy2 |
(x3 – 2√2 y3) = (x - √2y) (x2 + √2xy + 2y2) Using this in given expression: ⇒ (x2 + √2 xy + 2y2) = Ax2 + Bxy + Cy2 Comparing the coefficients: A = 1, B = √2, C = 2 Hence, (2A + 4√2 B – 4C) = (2 + 8 – 8) = 2 |