SSC CHSL 2021 PYQ — Question 56

SSC CHSL - 12 April 2021 - Shift 1 • Quantitative Aptitude • Q56

If x2 - 63\sqrt{3}x + 1 = 0, then the value of x3 + 1x3\frac{1}{x^3} will be:

Show answer & explanation

Correct answer: B

Explanation

 The correct answer is option 2 i.e. 630.

x2 - 6√3x + 1 = 0

⇒ x+1xx +\frac{1}{x} = 6√3

x3+1x3x^3 + \frac{1}{x^3}  + 3 × 6√3 = 648√3

⇒ x3+1x3x^3 + \frac{1}{x^3}  =  648√3 - 18√3

⇒ x3+1x3x^3 + \frac{1}{x^3}  = 630√3