If 8sin2 θ + 2cosθ = 5, 0º < θ < 90º, then the value of tan2 θ + sec2 θ - sin2 θ will be:
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Correct answer: C
Explanation
The correct answer is option 3 i.e.
8sin2θ + 2cosθ = 5
⇒ 8(1 - cos2θ) + 2cosθ = 5
⇒ 8 - 8cos2θ + 2cosθ = 5
⇒ 8cos2θ - 2cosθ - 3 = 0
⇒ 8cos2θ - 6cosθ + 4cosθ - 3 =0
⇒ 2cosθ(4cosθ - 3) + 1(4cosθ - 3) = 0
⇒ (2cosθ + 1)(4cosθ - 3) = 0
⇒ cosθ ≠ - 1/2, cosθ = 3/4
∵ cosθ = Base/ Hypotenuse = 3/4
By pythagoras theorem
Hypotenuse2 = Base2 + Perpendicular2
⇒ 42 = 32 + P2
⇒ P =
tan2θ + sec2θ - sin2θ = 7/9 + 16/9 - 7/16
⇒ (368 - 63)/144
The required answer = 305/144