SSC CHSL 2021 PYQ — Question 57

SSC CHSL - 12 April 2021 - Shift 1 • Quantitative Aptitude • Q57

If 8sin2 θ + 2cosθ = 5, 0º < θ < 90º, then the value of tan2 θ + sec2 θ - sin2 θ will be:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e.  305144\frac{305}{144}

sin2θ+cos2θ=1sin^2θ + cos^2θ = 1

8sin2θ + 2cosθ  = 5

⇒ 8(1 - cos2θ) + 2cosθ = 5 

⇒ 8 - 8cos2θ + 2cosθ = 5

⇒ 8cos2θ - 2cosθ - 3 = 0

⇒ 8cos2θ - 6cosθ + 4cosθ - 3 =0

⇒ 2cosθ(4cosθ - 3) + 1(4cosθ - 3) = 0

⇒ (2cosθ + 1)(4cosθ - 3) = 0

⇒ cosθ ≠ - 1/2, cosθ = 3/4

∵  cosθ = Base/ Hypotenuse = 3/4 

By pythagoras theorem 

Hypotenuse2 = Base2 + Perpendicular2

⇒ 42 = 32 + P2

⇒ P = 7 \sqrt7

tan2θ + sec2θ - sin2θ = 7/9 + 16/9 - 7/16

⇒ (368 - 63)/144

The required answer = 305/144