SSC CGL 2022 PYQ — Question 62

SSC CGL - 01 Dec 2022 - Shift 1 • Quantitative Aptitude • Q62

If x2 - 5x + 1 = 0, then find the value of x6+x4+x2+15x3\dfrac{x^6 + x^4 +x^2 + 1}{5x^3}. 

 

Show answer & explanation

Correct answer: C

Explanation

The correct answer is Option 3. i.e. 23.

According to the question,

x2 - 5x + 1 = 0

Dividing both sides by x, we get

x - 5 + 1/x = 0

⇒ x + 1/x = 5........(1)

Now we know that if x + 1/x = a,

then x3 + 1/x3 = a3 - 3a.......(2)

Thus solving the given equation,

= x6+x4+x2+15x3\dfrac{x^6 + x^4 +x^2 + 1}{5x^3}

= 1/5 × (x3 + x + 1/x + 1/x3)   

= 1/5 × (53 - 3 × 5 + 5)......................... by (1) and (2)

= 1/5 × (115)

= 23