SSC CHSL 2022 PYQ — Question 61

SSC CHSL - 24 May 2022 - Shift 1 • Quantitative Aptitude • Q61

If x + y + z = 0, then what will be the value of (x2yz)+(y2zx)+(z2xy)?(\frac{x^2}{yz})+(\frac{y^2}{zx})+(\frac{z^2}{xy})?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 3

Calculations:

We know that, x + y + z = 0 and

x3 + y3 + z3 = 3xyz

⇒ (x2yz)+(y2zx)+(z2xy)(\frac{x^2}{yz})+(\frac{y^2}{zx})+(\frac{z^2}{xy})

⇒ x3+y3+z3xyz\frac{x^3 + y^3 + z^3}{xyz}

⇒ 3xyzxyz\frac{3xyz}{xyz}

⇒ 3