A student multiplied a number by 3/5 instead of 5/3 . What is the percentage error in the calculation?

A student multiplied a number by 3/5 instead of 5/3 …

A student multiplied a number by $\frac{3}{5}$ instead of $\frac{5}{3}$ . What is the percentage error in the calculation?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 64

Calculations:

Let the number be x.

⇒ Wrong number = x × 3/5

⇒ correct number = x × 5/3

Difference = 5/3x - 3/5x = 16x/15

Required percentage = [(16x/15)/(5x/3)] × 100 = 64