If x-y-z=0, then the value of (x2 + y2 + z2) ÷ (y2 + xz) is:
Show answer & explanation
Correct answer: A
Explanation
The correct answer in option 1 i.e. 2
x + y + z = 0
This is only one equation and three variables are asked so let us assume y = 0
⇒ x + z = 0
⇒ x = - z
⇒ (x2 + y2 + z2) ÷ (z2 – xy)
⇒ [(-z)2 + z2] ÷ [ – (-z)z]
⇒ [z2 + z2] ÷ z2
⇒ 2z2 ÷ z2
⇒ 2