SSC CHSL 2021 PYQ — Question 74

SSC CHSL - 19 April 2021 - Shift 2 • Quantitative Aptitude • Q74

If x - y = 7/4 and 1x−1y=143\frac{1}{x}-\frac{1}{y}=\frac{14}{3} then x3  - y3 is equal to:-

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e.  21764\frac{217}{64}

Given:

  x - y = 7/4 

1x−1y=143\frac{1}{x}-\frac{1}{y}=\frac{14}{3}

Concept USed:

(x - y)3 = x3  - y3 - 3(xy)(x - y)

Explanation:

According o the given question,

 (y−x)xy=143{( y - x) \over xy}=\frac{14}{3}

⇒−74xy=143{-{7 \over 4} \over xy} = {14 \over 3} 

⇒ xy = −38-{3 \over 8}

Now, (x - y)3 = x3  - y3 - 3(xy)(x - y)

⇒ (74)3=x3−y3−3(−38)(74)({7 \over 4})^3 = x^3 - y^3 - 3(-{3 \over 8})({7 \over 4})

⇒ 34364=x3−y3+(6332){343 \over 64} = x^3 - y^3 + ({63 \over 32})

⇒34364−6332=x3−y3{343 \over 64} - {63 \over 32} = x^3 - y^3

⇒ x3−y3=21764 x^3 - y^3 = {217 \over 64}

Hence the required answer is 21764\frac{217}{64}.