SSC CHSL 2021 PYQ — Question 73

SSC CHSL - 19 April 2021 - Shift 2 • Quantitative Aptitude • Q73

If a4 + b4 + a2b2 = 133 and a2 + b2 - ab = 19, then the value of ab will be:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e. -6

Given:

a4 + b4+ a2b2 = 133 and

a2 + b² - ab = 19

Concept Used:

(a + b)2 = a2 + 2ab + b2

Explanation:

According to the given question,

a4 + b4 + a2b2 = 133 

⇒  a4 + b4 + 2a2b2 - a2b2 = 133

⇒ (a2 + b2)2 - a2b2 = 133   ....(i)

a2 + b² - ab = 19

⇒ a2 + b2 = 19 + ab   ...(ii)

Now putting value of eqation (ii) in equation (i), we get

⇒  (19 + ab)2 - a2b2 = 133

⇒ 361 + a2b2 + 38ab - a2b2 = 133

⇒ 38ab = 133 - 361

⇒ 38ab = -228

⇒ ab = −22838-228 \over 38 = -6

Hence the required answer is -6.