SSC CGL 2021 PYQ — Question 63

SSC CGL - 18 Aug 2021 - Shift 1 • Quantitative Aptitude • Q63

If x + y = 3 and 1x\frac{1}{x}+1y\frac{1}{y}= -310\frac{3}{10}, then the value of (x2 + y2) is:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 29

It is given that,

 x + y = 3 and 1x\frac{1}{x}+1y\frac{1}{y}= -310\frac{3}{10}.

⇒ 1x\frac{1}{x}+1y\frac{1}{y}= -310\frac{3}{10}.

⇒ 10(x + y) = -3xy

⇒ -10 = xy.

⇒ (x + y)2 = 32

⇒ x2 + y2 + 2xy = 9

⇒ x2 + y2 = 9 + 20 = 29