SSC CHSL 2022 PYQ — Question 56

SSC CHSL - 3 June 2022 - Shift 1 • Quantitative Aptitude • Q56

If x - 2y = 3 and 2xy = 5, then find the value of (x + 2y)2.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 29

Given:

x - 2y = 3 and

2xy = 5 

⇒ xy = 5/2

(x - y)2 = x2 + y2 - 2xy

(x + y)2 = x2 + y2 + 2xy

Explanation:

According to the given question,

(x - 2y)2 = 9

⇒ x2 + 4y2 - 4xy = 9

⇒ x2 + 4y2 = 9 + 4xy

⇒ x2 + 4y2  = 9 + 4 × (5/2)

⇒ x2 + 4y2 = 9 + 10 

⇒ x2 + 4y2 = 19

Now, (x + 2y)2 = x2 + 4y2 + 4xy 

⇒ (x + 2y)2 = 19 + 4 × (5/2)

⇒ (x + 2y)2 = 29

Hence the required answer is 29.