If x + 1/x , = 10 then find the value of 7x/(x²+1-8x)

If x + $\frac{1}{x}$ , = 10 then find the value of $\frac{7x}{x^2+1-8x}$

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 3.5.

Given,

x + $\frac{1}{x}$ , = 10, or x² + 1 = 10x

Now substituting the value of x² + 1 in $\frac{7x}{x^2+1-8x}$

= $7x\over10x - 8x$ = 7x/2x = 3.5

SSC CHSL 2022 PYQ — Question 60