SSC CGL 2022 PYQ — Question 52

The correct answer is Option 3 i.e.119 .

$\frac{4\left [ \left ( 17 \right )^{3} -\left ( 7 \right )^{3}\right ]}{\left ( 17 \right )^{2}+7^{2}+p}=40$

$\frac{4\left [ 4913-343 \right ]}{289+49+p}=40$

$\frac{4\times 4570}{338+p}=40$

$\frac{18280}{338+p}=40$

$18280 = 40\left ( 338+p \right )$

18280 = 13520 + 40p

4760 = 40p

So,

p = 119