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SSC Selection Post 2020 PYQ — Question 57

SSC Selection Post - Matriculation Level - 9 Nov 2020 - Shift 3 • Quantitative Aptitude • Q57

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If the speed of a train is increased by 30%, it takes 36 minutes less to cover the same distance. What is the time taken (in hours) to cover the same distance with the original speed?

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Correct answer: D

Explanation

The correct answer is option 4 i.e. 2.6.

Distance = Speed × Time

⇒ S ⋅ T = 1.3S ⋅ (T−0.6)

⇒ T = 1.3(T - 0.6)

⇒ T = 1.3T - 0.78

T−1.3T=−0.78⇒−0.3T=−0.78⇒T=0.780.3=2.6T - 1.3T = -0.78 \Rightarrow -0.3T = -0.78 \Rightarrow T = \frac{0.78}{0.3} = 2.6